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126=14x^2
We move all terms to the left:
126-(14x^2)=0
a = -14; b = 0; c = +126;
Δ = b2-4ac
Δ = 02-4·(-14)·126
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*-14}=\frac{-84}{-28} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*-14}=\frac{84}{-28} =-3 $
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